The number of windings on the primary coil of a transformer is 1.5 times greater than on the secondary coil. The primary
coil has a current of 3.0 A and a voltage of 12.0 V. Determine
the voltage and current on the secondary coil.

I. Vs = 8.0 Volts.

II. Is = 4.5 Amperes.

Explanation:

Given the following data;

Np = 1.5Ns =  ..... equation 1

Ip = 3.0 A

Vp = 12 V

To find the voltage and current on the secondary coil;

I. For the voltage in the secondary coil (Vs), we would use the following formula;

 ...... equation 2.

Substituting eqn 1 into eqn 2, we have;

Cross-multiplying, we have;

Vs = 8.0 V

II. For the current in the secondary coil (Is), we would use the following formula;

 .... equation 3

Substituting eqn 1 into eqn 3, we have;

Cross-multiplying, we have;

Is = 4.5 A

real, smaller and upside-down.   so the answer should be b.

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