A car moving at 41.35 m/s hits a brick wall and stops in 0.140 s. What is the acceleration of the car?

Acceleration, a = 295.36 m/s²

Explanation:

Given the following data;

Final velocity = 41.35 m/s

Initial velocity = 0 m/s

Time = 0.140 seconds

To find the acceleration, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

41.35 = 0 + a*0.140

41.35 - 0 = 0.140a

41.35 = 0.140a

Acceleration, a = 41.35/0.140

Acceleration, a = 295.36 m/s²

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