Una caja de 30 N es empujada desde el reposo en línea recta por una fuerza F, como muestra la figura;haciéndola acelerara 2,2 m/s2, determine el valor de la fuerza F

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation:

the correct answer is "inertia"