An ideal parallel plate capacitor with a cross-sectional area of 0.4 cm2 contains a dielectric with a dielectric constant of 4 and a dielectric strength of 2 x 108 V/m. The separation between the plates of the capacitor is 5 mm. What is the maximum electric charge (in nC) that can be stored in the capacitor before dielectric breakdown

Explanation:

Given

Cross-sectional area

Dielectric constant

Dielectric strength

Distance between capacitors

Maximum charge that can be stored before dielectric breakdown is given by

The maximum charge is 7.08 x 10^-8 C.

Explanation:

Area, A = 0.4 cm^2

K = 4

Electric field, E = 2 x 10^8 V/m

separation, d = 5 mm = 0.005 m

Let the capacitance is C and the charge is q.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

the right answer is 0.3 meters per second