Physics, 11.07.2021 18:00 jwjohnson20
650 m [N37ºW], then 520 m [E], then 330 m [S30.0ºW]. He didn't find it! So he returned empty handed. He took the shortest path to go back where he started. If it took him 1.0 hour to get back, what was his average velocity for the return trip only (in m/s)?
Answers: 3
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650 m [N37ºW], then 520 m [E], then 330 m [S30.0ºW]. He didn't find it! So he returned empty handed....
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