A 1.25cm diameter cylinder is subjected to a load of 2500kg. Calculate the stress on the bar in mega pascal

200 Mpa

Explanation:

Given that diameter of cylinder = d = 1-25cm = 1.25 100 =0.0125m

Load or mass = m = Stress 0 = ? 2500kg

Solution: Formula N = F A

Area of Cross-section of cylinder = A=πr2 A = π(d/2) 2

= π(d2/4)

=(3.14)(0.0125)2/4

A = 1.226x10-4

F ・ mg = = F A 24500 2500 x 9.8 = 24500 N

1-226x10-4

1998 36 867.9

= 200 x 106 Pa

= 200 MPa

*Hope it helps you*

Good luck

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

double the distance = divide strength by 4