100 g of water are cooled and the enthalpy change is -12,540 J. What is the change in temperature of the water?

-29.9907

Explanation:

c = Q / (mΔT)

You're looking for ΔT, so you would plug in what you already know and get C= -12540/(100 x ΔT)

then you would solve

as technology advances, new experiments often expose problems in accepted theories. c

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-lavira: )

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not copied too! hope this !

joke:

h o h o hope you have a merry christmas!