The mass per unit length of the rope is 0.0500 kg/m. Find the tension. Express your answer in newtons.

Complete question:

A transverse wave on a rope is given by . The mass per unit length of the rope is 0.0500 kg/m. Find the tension. Express your answer in newtons.

The tension on the rope is 1.95 N

Explanation:

The general equation of a progressive wave is given as;

Compare the given equation with the general equation of wave, the following parameters will be deduced.

A = 0.75 cm

k = 0.400π cm⁻¹

ω = 250π s⁻¹

The frequency of the wave is calculated as;

ω = 2πf

2πf = 250π

2f = 250

f = 250/2

f = 125 Hz

The wavelength of the wave is calculated as;

The velocity of the wave is calculated as;

v = fλ

v = 125 x 0.05

v = 6.25 m/s

The tension on the rope is calculated as;

Therefore, the tension on the rope is 1.95 N

the answer is a. at the equator

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be