An air-track glider attached to a spring oscillates between the 13.0 cm mark and the 65.0 cm mark on the track. The glider completes 13.0 oscillations in 40.0 s . You may want to review (Pages 391 - 393) . Part A What is the period of the oscillations

Answer(b) both involve the use of levers;

Lexy is correct because angle r is between the incident wave,  n  = 0, and a diffracted wave.

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !