A student jumps from a flat surface with an initial velocity of 15ms. If the distance covered is 3m. What is the acceleration due to gravity and the time?

the acceleration due to gravity, g is zero (0)

the time of the motion is 0.2 s

Explanation:

Given;

initial velocity of the student, u = 15 m/s

distance traveled by the student, x = 3 m

The motion of the student is directed towards the horizontal and the acceleration due to gravity, g is zero (0).

The time of the motion is calculated as;

x = ut + ¹/₂gt²

x = ut + ¹/₂(0)t²

x = ut

t = x/u

t = 3 / 15

t = 0.2 s

Therefore, the time of the motion is 0.2 s

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