How far above the bottom of the tank could a second hole be cut so that the stream emerging from it could have the same range as for the first hole

hello your question is incomplete below is the complete question

Water stands at a depth H in a large open tank whose side walls are vertical  . A hole is made in one of the walls at a depth h below the water surface. Part B How far above the bottom of the tank could a second hole be cut so that the stream emerging from it could have the same range as for the first hole

answer :

At Height ( h ) from the bottom of Tank

Explanation:

Determine how far above the bottom of the tank a second hole be cut

For the second hole to have the same range as the first hole

Range of first hole = Velocity of efflux of water * time of fall of water

                               =  √ (2gh) * √( 2g (H - h) / g)

                               = √ ( 4(H-h) h)

Hence the Height at which the second hole should be placed to exercise same range of stream emerging = h from the bottom of the Tank

i don't know that i agree with that but what's the question ?

this could be newton#'s law of cooling. the cooling curve is exponential