A circular solenoid has 100 loops per centimeter, a radius of 4.53 cm, a length of 8.88 cm, and carries a current of 500 mA. It's inductance is: a) 7.75 mH
b) 71.9 mH
c) 18.0 mH
d) 0.912 mH

The inductance of the solenoid is 71.98 mH

Explanation:

Given;

number of loops per length of the solenoid, n = 100 loops/cm

radius of the solenoid, r = 4.53 cm

length of the solenoid, L = 8.88 cm

current carried by the solenoid, I = 500 mA

The inductance of the solenoid is calculated as;

where;

A is the area of the coil

N is the number of turns, = 100 x 8.88 = 888 loops

l is the length = 0.0888 m

Therefore, the inductance of the solenoid is 71.98 mH

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

the device is called “ rocket engine”