when a wooden block floats in water displaces 0.006 cubic of the water find the weight of the wooden block when it is in air​

solve it with the formula 1−0.4=0.6, 0.6Vρg=Vρbg where ρb 

Explanation:

The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.

The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=

The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.

The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.In the second case: 1.5fVρg=Vρbg+Vρba=1.5Vρbg⇒fρ=ρb⇒f=0.6.

The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.In the second case: 1.5fVρg=Vρbg+Vρba=1.5Vρbg⇒fρ=ρb⇒f=0.6.Thus, the fraction of immersed volume remains the same.

The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.In the second case: 1.5fVρg=Vρbg+Vρba=1.5Vρbg⇒fρ=ρb⇒f=0.6.Thus, the fraction of immersed volume remains the same.Body will float with 40% of the volume above water surface.