In each of the following cases, the mass is [06] kg and the radius is 7.50 cm. (a) What is the moment of inertia (kg m2 ) of a solid cylinder rotating about an axis parallel to the symmetry axis but passing through the edge of the cylinder

Explanation:

Parallel axis theorem

I = ½mR² + mR² = 3mr²/2

Not exactly sure what your mass is supposed to be, so I'll let you calculate your own moment of inertia

IF mass is 0.6 kg,

THEN the result would be

I = 3(0.6)(0.075²)/2 = 0.0050625 kg•m²

conservation of mass

mass before something happens = mass afterwards

answer is slate

hope this