The average speed of molecules of a 0.1 mole nitrogen gas in a container is 5103 m/s.
a/ Determine the total translational kinetic energy of the gas.
b/ Compute the energy as heat providing to the gas so that the average speed of its molecules increases to
double.

(a) The total translational kinetic energy of the gas is .

(b) The energy as heat providing to the gas so that the average speed of its molecules increases to double is .

Explanation:

Given: Average speed of molecules = m/s

Moles = 0.1 mol

(a) As the give gas is nitrogen so its mass is 28 g/mol.

Formula to calculate translational kinetic energy is as follows.

Total translational K.E =

where,

m = mass

v = velocity

Substitute the values into above formula as follows.

(b) As the energy is directly proportional to the square of velocity. So, when average speed of molecules increases to double then relation between energy and velocity will be as follows.

This means that velocity gets one-fourth times the energy of its molecules.

Therefore, energy will be calculated as follows.

Therefore, we can conclude that

(a) The total translational kinetic energy of the gas is .

(b) The energy as heat providing to the gas so that the average speed of its molecules increases to double is .

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explanation: