A 70 jug astronaut is floating free in space several meters from her spacecraft. She is holding a1.6 kg wrench which she can hurl with a speed of 22.0 m/s. What will be her speed towards the spacecraft?

0.5 m/s

Explanation:

In  solving this, we would be applying the principle of conservation of momentum. This states that momentum is conserved, and thus, Initial momentum has to be equal to the final momentum. This also means that it can be related by the formula

M * u = m * v, where

M = mass of the astronaut

m = mass of the wrench

u = speed of the astronaut

v = final speed of the wrench

70 * u m/s = 1.6 * 22 m/s

70u = 35.2 m/s

u = 35.2/70

u = 0.5 m/s

i think its

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong