Physics, 20.06.2021 18:20 misa11234

The equation of damped oscillations is given in the form x=0.05e^-0.25sin½πt (m). Find the velocity of an oscillating point at the moments of time: 0, T, 2T, 3T and 4T.

The equation of damped oscillations is given in the form x=0.05e^-0.25sin½πt (m). Find the velocity

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Answer from: brianogle4069

Explanation:

The logarithmic damping decrement of a mathematical pendulum is DeltaT=0.5. How will the amplitude of oscillations decrease during one full oscillation of the pendulum

Answer from: sierram298

Explanation:

ω = π/2 = 2π/T

T = 2π/(π/2) = 4 s

velocity is the derivative of position

v(t) = (-1/80)(e^(-t/4)[sin(πt/2) - 2πcos(πt/2)]

0T = v(0) = (-1/80)(e^(-0/4)[sin(π0/2) - 2πcos(π0/2)] = 0.078540

T = v(4) = (-1/80)(e^(-4/4)[sin(π4/2) - 2πcos(π4/2)] = 0.028893

2T = v(8) = (-1/80)(e^(-8/4)[sin(π8/2) - 2πcos(π8/2)] = 0.010629

3T = v(12) = (-1/80)(e^(-12/4)[sin(π12/2) - 2πcos(π12/2)] = 0.003910

4T = v(16) = (-1/80)(e^(-16/4)[sin(π16/2) - 2πcos(π16/2)] = 0.001439

Answer from: Quest

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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The equation of damped oscillations is given in the form x=0.05e^-0.25sin½πt (m). Find the velocity...

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