A ball is thrown horizontally from the top of a building 59 m high. The ball strikes the ground at a point 65 m horizontally away from and below the point of release. What is the speed of the ball just before it strikes the ground

Explanation:

We are looking for final velocity. Since the ball is thrown horizontally, there is no upwards velocity, so the y dimension here is only useful to us for finding how long the ball was in the air. In the y dimension, here's what we know:

a = -9.8 m/s/s

Δx = -59 m

(again, initial upwards velocity is 0 because the ball was thrown horizontally)

We can put all that together in the equation:

Δx = and filling in:

which simplifies to

and solving for t:

and

t = 3.5 sec

Now we can use that time in the d = rt equation, which is all we need for the horizontal dimension (I'll show you why in just a second). In the horizontal dimension, here's what we know:

a = 0 m/s/s

Δx = 65 m

t = 3.5 sec

Putting that all together in our one-dimensional equation for displacement:

Δx = and acceleration is 0, we can simplify that down to

Δx = which is the exact same thing as d = rt where r is the velocity we are looking for. Filling in:

65 = v(3.5) so

v = 18.6 m/s

That's the velocity with which the ball strikes the ground.

would be false hope this out

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!