g A car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration

8761.5 N

Explanation: Given that a car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration

Mass m = 1120kg

First change km/h to m/s

(80 × 1000) ÷ 3600

Velocity = 22.2 m/s

Acceleration = ( 22.2 - 0 ) ÷ 10

Acceleration = 2.2 m/s^2

Force F1 = mass × acceleration

Substitutes all the parameters into the formula

F1 = 1120 × 2.2

F1 = 2489 N

For the car to come to rest, it will be decelerating.

Using 3rd law of motion

V^2 = U^2 + 2as

V = 0 since it is coming to rest.

Substitute all the parameters into the formula

0 = 22.2^2 - 2 × a × 44

88a = 492.84

a = 492.84/88

a = 5.6 m/s^2

The force F2 = 1120 × 5.6

F2 = 6272.5N

Net force = 6272.5 + 2489

Net force = 8761.5 N

Therefore, the net force is 8761.5 N

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

nah.   i'm just sleepy.