Justhin and Christian have masses of 74 kg and 64 kg, respectively. They stand 0.5 m apart. If there were no other forces acting on them, what gravitational force would they be exerting on each other?

ans: 1.26 × 10^(-6) N

Explanation:

suppose that;

mass of Justhin ( m) = 74 kg

mass of Christian (M) = 64 kg

distance of separation (d) = 0.5 m

universal gravitational constant(G) =6.67 × 10^(-11) Nm²/kg²

so,

gravitational force between them(F) = GmM/d²

F = (6.67 × 74× 64)/ ( 10¹¹× 0.5²)

= (1.26 × 10⁵)/ 10¹¹

= 1.26 × 10^(-6) N

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6