A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ? 70 N
80 N
75 N
85 N

75 N

Explanation:

Given that,

The angle of incline of the ramp is 42°.

The gravitational force of the box, W = 112.1 N

We need to find the force of static friction on the box.

We have that the component of the gravitational force acting along the inclined plane i.e.

So, the force of static friction is equal to 75 N.

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =