A car accelerates uniformly from rest to a speed of 55.0 mi/h in 13.0 s. (a) Find the distance the car travels during this time. m (b) Find the constant acceleration of the car. m/s2

(a) 159.84 m

(b) 1.89 m/s²

Explanation:

Applying,

(a)

s = (v+u)t/2 Equation 1

Where s = distance traveled by the car, u = initial velocity, v = final velocity, t = time.

From the question,

Given: u = 0 m/s ( from rest), v = 55 mi/h = (55/2.237) m/s = 24.59 m/s, t = 13 s

Substitute these values into equation 1

s = (24.59+0)13/2

s = 159.84 m

(b)

Also applying,

a = (v+u)/t Equation 2

Where a = acceleration of the car.

substituting into equation 2,

a = (24.59+0)/13

a = 1.89 m/s²

this means that the temperature of both substances will be equal