a jeep start from the state of rest .if ots velocity became 60km/hr in 15 min. (i) what is the acceleration of the jeep?(ii) what is the distance coverd by jeep?​

Explanation:

Here,

Converting the quantities into its standard form :

→ v = 60 km/h

→ v = ( 60 × ) m/s

→ v = ( 10 × ) m/s

→ v = m/s

→ v = 16.66 m/s

Also,

→ t = 15 minutes

→ t = (15 × 60) seconds

→ t = 900 seconds

★ v = u + at

→ 16.66 = 0 + 900a

→ 16.66 - 0 = 900a

→ 16.66 = 900a

→ = a

→ 0.0185 m/s² = a

∴ Acceleration is 0.0185 m/s².

★ v² - u² = 2as

→ (16.66)² - (0)² = 2 × 0.0185 × s

→ 277.5556 - 0 = 0.037s

→ 277.5556 = 0.037s

→ = s

→ 7501.50 m = s

∴ Distance covered is 7501.50 m .

mass and volume are the answers you are looking for