what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

The horizontal component of the vector, Rₓ ≈ -16.06

The vertical component of the vector, R = × sin(θ)

∴  R = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, R ≈ 19.15

(The vector, R = Rₓ + R

= Rₓ·i + R·j

∴ ≈ -16.07·i + 19.15j)

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