Acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N

Question: Find acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N, If the mass of the refrigerator is 10 kg.

40 m/s²

Explanation:

Applying,

F = maEquation 1

Where F = Force applied to the refrigerator, m = mass of the refrigerator, a = acceleration of the refrigerator.

make a the subject of the equation

a = F/m Equation 2

From the question,

Given: F = 400 N, m = 10 kg

Substitute these values into equation 2

a = 400/10

a = 40 m/s²

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

i believe the answer is electric potential.

explanation: