2. A charge particle is moved through a potential difference of 154.5 V and experiences a
change of electric potential energy of 4.26 x 10-8 J. What is the charge of the particle?

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

it will be pushed away from the source of the electric field. a negative charge in a cloud induces a positive charge in the ground below the cloud.

explanation:

d they tend to lose electrons and become cations.

explanation: