Physics, 02.06.2021 21:00 chefdnguyen

75 points A carnival ride initially rotates counterclockwise at 2.0 rad/s but comes to rest with a constant acceleration over an angular displacement of 6.0 rad. What is the angular acceleration?

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Answer from: krystalhurst97

a) v = 13.8 m / s , b) a = 95.49 m / s² , c) a force that goes to the center of the carnival ride and d) μ = 0.10

Explanation:

For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics

a) reduce the magnitudes to the SI system

w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s

The equation that relates linear and angular velocity is

v = w r

v = 6.91 2

v = 13.8 m / s

b) centripetal acceleration is given by

a = v² / r = w² r

a = 6.91² 2

a = 95.49 m / s²

c) this acceleration is produced by a force that goes to the center of the carnival ride

d) Here we use Newton's second law

fr -W = 0

fr = W

μ N = mg

Radial shaft

N = m a

N = m w² r

μ m w² r = m g

μ = g / w² r

μ = 9.8 / 6.91² 2

μ = 0.10

a) v = 13.8 m / s , b) a = 95.49 m / s² , c) a force that goes to the center of the carnival ride and d) μ = 0.10

Explanation:

For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics

a) reduce the magnitudes to the SI system

w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s

The equation that relates linear and angular velocity is

v = w r

v = 6.91 2

v = 13.8 m / s

b) centripetal acceleration is given by

a = v² / r = w² r

a = 6.91² 2

a = 95.49 m / s²

c) this acceleration is produced by a force that goes to the center of the carnival ride

d) Here we use Newton's second law

fr -W = 0

fr = W

μ N = mg

Radial shaft

N = m a

N = m w² r

μ m w² r = m g

μ = g / w² r

μ = 9.8 / 6.91² 2

μ = 0.10

Explanation:

Answer from: Quest

12000j is work done

Answer from: Quest

Centrapedial force is the answer

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75 points A carnival ride initially rotates counterclockwise at 2.0 rad/s but comes to rest with a...

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