18 kilogram Mass Blokus addressed a level surface if the coefficient of static friction between the Block in the surface is 0.6 what is horizontal force is required to take gravity 10m/s2 ​

Question: 18 kilogram Mass Block rest on level surface if the coefficient of static friction between the Block and the surface is 0.6 what  horizontal force is required to just move the blcok ( take gravity as 10m/s2 )

108 N

Explanation:

From the question,

Applying

F' = mgμ Equation 1

Where F' = Frictional force = horizontal  force required to just move the block,  m = mass of the block, g = acceleration due to gravity, μ = coefficient of static friction.

From the question,

Given: m = 18 kg, μ = 0.6, g = 10 m/s²

Substitute these values into equation 1

F' = 18×0.6×10

F' = 108 N

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