A 330.-ohm resistor is connected to a 5.00-volt battery. What is the current through the resistor?

I = 0.0152 A = 15.2 mA

Explanation:

Using Ohm's law,

V = IR or

I = V/R

= (5.00 V)/(330. ohms)

= 0.0152 A

= 15.2 mA

From Ohms Law

V=IR

V=5volts

R=33.0hms

I=V/R

I= 5/33

=0.152A

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