A 20 ohm and 60 ohm light bulb are put in series together which one would be brighter?

The 60 Ohm bulb would be brighter than the 20 Ohm bulb.

Explanation:

Hi there!

Ohm's Law: where V is voltage, I is current and R is resistance

Power equation:

The greater the power of a bulb, the brighter it is.

The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:

Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.

I hope this helps!

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.