(121 m/s, or 43 4. The pilot of an airplane, which has been diving at a speed of
540 km/h, pulls out of the dive at constant speed.
(a) What is the minimum radius of the plane's circular path in
order that the acceleration of the pilot at the lowest point
will not exceed 7 g?
(b) What force is applied on an 80 kg pilot by the plane seat at
the lowest point of the pull-out? (328 m, 6.3 X 10N)

(a) r = 328 m

(b) F = 6271.8 N

Explanation:

speed, v = 540 km/h = 150 m/s

Acceleration, a = 7 g

(a) Let the radius is r.

(b) The force on 80 kg pilot at the lowest point is

a coal burning power plant

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.