An attractive force of |1N| exists between two charged particles. The magnitude of both charges is the same. If the particles are 0.25m apart what is the value and sign of the charge for both particles. A. (- 2.6x10-6 C) and (+ 2.6x10-6 C)

B. (+ 2.7x10-11 C) and (- 2.7x10-11 C)

C. (- 5.27x10-6 C) and (+ 5.27x10-6 C)

D. (- 6.94x10-12 C) and (- 6.94x10-12 C)

A: -2.6 × 10^(-6) C and 2.6 × 10^(-6) C

Explanation:

According to coulombs law, the formula for the force between 2 charged particles is;

F = kq1•q2/r²

Where;

F is Force = |1N|

q1 and q2 are the charges of both particles

k is coulombs constant = 9 × 10^(9) N.m²/C²

r is distance between particles = 0.25

Now, the force |1N| means -1 or +1

Thus;

-1 = 9 × 10^(9) × q1•q2/(0.25)²

Or

1 = 9 × 10^(9) × q1•q2/(0.25)²

Thus;

q1•q2 = -6.94 × 10^(-12)

Or q1•q2 = 6.94 × 10^(-12)

Now, we are told that the magnitude of both charges are the same.

Thus;

q² = 6.94 × 10^(-12)

q = √(6.94 × 10^(-12))

q = 2.6 × 10^(-6) C

Since from earlier, we saw that;

q1•q2 = -6.94 × 10^(-12)

Or q1•q2 = 6.94 × 10^(-12)

Thus means that one of the charges will be negative while the other will be positive.

Thus, the charges are;

-2.6 × 10^(-6) C and 2.6 × 10^(-6) C

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

where is the circuit diagram ?