Please help i'm going to throw up from stress Water at 20.0 °C is mixed with 120.0 g of ethyl alcohol at 10.0 °C in a thermally insulated container. If the final mixture has a temperature of 16.0 °C, how much water was added?

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Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

and

and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

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