Physics, 30.05.2021 09:10 gracekerleyy

Is there any difference between antimatter, dark matter, dark energy, and degenerate matter? pakisagutan po need ko na yan ngayon

answer this please

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Answer from: tytianadyson74

Explanation:

antimatter - counterpart of ordinary matter; identical in every way except for charge. Examples are positrons (counter to electrons) and antiprotons (counter to protons). Direct contact between matter and antimatter results in total annihilation accompanied by huge radiation output.

dark matter - hypothesized as the non-visible or not directly observable kind of matter that could explain some of the unusual behavior of stars and galaxies.

dark energy - hypothesized to be some kind of a repulsive force like anti-gravity that could explain the apparent accelerated rate of expansion of the universe.

degenerate matter - a very dense form of matter made up of fermions (like protons and neutrons) only. Some stars are believed to be made of degenerate matter.

Answer from: ashlpiriz123

Yes. Although the names sound vague and almost fictional, the types of matter called antimatter, dark matter, dark energy, and degenerate matter are all different, specific entities that really exist in our universe. ... Antimatter is just regular matter with a few properties flipped, such as the electric charge.

#Captainpower

Answer from: Quest

Yup no bull frogs here man

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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