A typical muscle fiber is 2.0 cm long and has a cross-section area of 3.1×10−9m2. When the muscle fiber is stimulated, it pulls with a force of 1.3 mN. What is the work done by the muscle fiber as it contracts to a length of 1.6 cm?

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

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