If the earth rock takes 2.00 s to reach its highest point, how long will it take the moon rock to do so

12.0 s

Explanation:

First, let's find the initial vertical velocity of the rock on earth. We know that

vy = v0y - gt

where g = 9.8 m/s^2. When the rock reaches its highest point, vy = 0. So if it takes 2.00 s to reach the maximum height, the initial velocity of the rock is

v0y = (9.8 m/s^2)(2.00 s) = 19.6 m/s.

We know that the moon only has 1/6 of earth's gravity. Therefore, if the same rock is given the same vertical velocity as on earth, then the time it takes to reach its maximum height is

voy = gt ---> t = voy/g

t = (19.6 m/s)/(9.8/6 m/s^2)

= 12.0 s

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.