Why do scientists need an accurate atomic model? (2 points) The atom is the most important structure in the universe. The atom is the most important structure in the universe. It allows scientists to predict things about objects that are too small to see. It allows scientists to predict things about objects that are too small to see. Models allow scientists to avoid having to do real experiments. Models allow scientists to avoid having to do real experiments. The atom cannot be divided into smaller particles.

1.

It allows scientists to predict things about objects that are too small to see.

Explanation:

Atomic models are crucial to the scientific study of atoms. Through models, we represent atoms that we actually cannot see. Observation based study and testing is done through that model which helps us find flaws in one model so that a better model is made. In this way, it is helpful to study about atoms through atomic models.

2.

The correct step in a scientific experiment involving acids and bases is:

Using an indicator to measure the hydrogen ion concentration of a solution.

Explanation:

Two acids can never neutralize each other. The pH of a neutral solution is 7. Whereas pH of an acid is always less than 7.

Indicators are used to measure the pH of solutions. They give different colors in solutions with different solutions. So, in an experiment to check if the solution is acidic or basic, we need to measure its hydrogen ion concentration for which an indicator is used.

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b

Explanation:

i took the test

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j