If 30.45 grams of water is to be heated up 3.3 degrees to make baby formula, how much heat must be added? The specific heat of water is
4.18 J/g °C.

A. 420 J
B. 281 J
C. 1604 J
D. 410 J

A. 420 J

Explanation:

Given the following data;

Mass = 30.45 g

Specific heat capacity = 4.18 J/g °C.

Temperature = 3.3°C

To find the quantity of heat;

Heat capacity is given by the formula;

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature.

Substituting into the equation, we have;

Q = 420.03 ≈ 420 Joules

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