2. Electrons are accelerated in the picture tube of a-television through a po- tential difference of 8.00 x 10^3 V. (Use the values q e=1.60 x 10^-19
kg and
m e = 9.109 x 10^-31 kg.)
a. What is the change in the potential energy of each electron traveling
in this tube?
b. What is the change in the kinetic energy of the electrons?
c. At what speed do the electrons hit the screen?
(Please help !!)

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s