Two protons are held a distance d apart. The electrostatic force and the gravitational force that one proton exerts on the other are Fe and Fg, respectively. Which of the following correctly compares the magnitude and direction of these forces? Fe > Fg, opposite direction

a. Fe > Fg, same direction
b. Fe < Fg opposite direction
c. Fe < Fg same direction

Explanation:

charge on each proton = 1.6 x 10⁻¹⁹ C

mass of proton = 1.67 x 10⁻²⁷ kg

Electrostatic force of repulsion Fe = 9 x 10⁹ x ( 1.6 x 10⁻¹⁹ )² / d²

= 23.04 x 10⁻²⁹ / d²

Gravitational  force of attraction = G Mm / d²

M = m = 1.67 x 10⁻²⁷ kg

Gravitational  force of attraction  Fg = 6.67  x 10⁻¹¹ x ( 1.67 x 10⁻²⁷ )² / d²

= 18.60 x 10⁻⁻⁶⁵ / d²

So Fg is far less than Fe and former is attractive , later is repulsive .

Fe > Fg, opposite direction , is the answer .

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

its c i just checked it