What kind of image is formed by an object that is placed beyond the center of curvature on the principal axis of a concave mirror? A.
real, inverted, the same size as the object, and at the same distance as the object
B.
real, inverted, larger than the object, and farther from the mirror than the object
C.
virtual, upright, left-right reversal, the same size as the object, and at the same distance as the object
D.
real, inverted, smaller than the object, and closer to the mirror than the object
E.
virtual, upright, larger than the object, and farther from the mirror than the object

D.

Real, inverted, smaller than the object, and closer to the mirror than the object

Explanation: Real images will be inverted. As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft