Which nucleus completes the following equation?

Option D. ⁸⁵₃₆Kr

Explanation:

⁸⁵₃₅Br —> ⁰₋₁e + ?

Let ⁿₘZ represent the unknown.

Thus, the equation becomes:

⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ

Next, we shall determine n, m and Z as follow:

85 = 0 + n

85 = n

Thus,

n = 85

35 = –1 + m

Collect like terms

35 + 1 = m

36 = m

Thus,

m = 36

ⁿₘZ => ⁸⁵₃₆Z = > ⁸⁵₃₆Kr

Thus, the equation:

⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ

Becomes:

⁸⁵₃₅Br —> ⁰₋₁e + ⁸⁵₃₆Kr

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!

pretty sure it's false