A 120 Ohm resistor is connected in series with a 180 Ohm resistor, and
attached to a battery. The voltage drop
across the 120 Ohm resistor is 6.00 V.
What is the voltage drop across the
180 Ohm resistor?
(Hint: How much current is flowing?)
(Unit = V)

I=0.05 Amper

v=9 volts

Explanation:

I=V/R1

l=6/120=0.05Amper

voltage of 180ohm =IR2=0.05×180=9volts

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