Bumper car A (67.3 kg) moves at 5.65 m/s left before colliding elastically with Car B (65.2 kg), which was initially moving 3.20 m/s right. After the collision, Car B moves to the left at 5.38 m/s. Find the velocity of car A after the collision.

2.66 m/s to the right

Explanation:

Applying,

The Law of conservation of momentum,

For elastic collision,

mu+m'u' = mv+m'v' Equation 1

Where m = mass of Car A, m' = mass of car B, u = initial velocity of car A, u' = Initial velocity of car B, v = Final velocity of car A, v' = Final velocity of car B

make v the subject of the equation

v = (mu+m'u'-m'v')/m Euqation 2

Note: Assuming Left direction is positive and right direction is negative.

Given: m = 67.3 kg, m' = 65.2 kg, u = 5.65 m/s, u' = -3.2 m/s, v' = 5.38 m/s

Substitute these values into equation 2

v = [(67.3×5.65)+(65.2×[-3.2])-(65.2×5.38)]/67.3

v = (380.245-208.64-350.776)/67.3

v = -179.17/67.3

v = -2.66

Hence v = 2.66 m/s to the right

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.