Four point masses are connected by rods of negligible mass and form a square with sides of length 32.2 cm. Three of the masses are 1.5 kg and one is 3.0 kg. How far from the 3.0 kg mass is the center of mass of the system

Solution :

Placing the mass at the and line up the square up with the axes.

Therefore,  r =

It s given that the side of the square is a = 32.2 cm

So, r

       = 18.21 cm

So the distance of the 3 kg mass from the center of mass, r= 18.21 cm

spectral lines lyman is one set

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards