A spherical conducting shell has an inner radius of 0.2 m and an outer radius of 0.4 m. There is no charge on the outer surface but the shell does have a nonzero net charge. All charges remain at rest. The potential at the outer surface is -2 V. The potential at the center of the cavity is g

Explanation:

From the question we are told that:

Inner radius

Outer radius

Potential at the outer surface is

Generally the equation for Potential at the outer surface P_o  is mathematically given by

Therefore

Generally the equation for Potential at Center of outer cavity  is mathematically given by

Therefore the potential at the center of cavity

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.