75 J of heat are added to a heat engine and 50 J of thermal energy is lost in the process. Determine the work done by the engine (in Joules)?

The work done by the engine is 50 J.

Explanation:

Given;

amount of heat energy added to the heat engine, Q = 75 J

energy lost in the process, E = 50 J

let the work done by the engine (system) = W

Apply the first law of thermodynamic;

ΔU = Q - W

where;

ΔU is change in internal energy = 75 J - 50 J = 25 J

25 = 75 - W

25 - 75 = - W

-50 J = - W

W = 50 J

Therefore, the work done by the engine is 50 J.

good for her? ? where is the question?

1/0.14nm = 10^10/1.4 a lot