5- A 2.0 kg block of aluminum (specific heat = 897 J/kg·K) is at an initial temperature of 300 K. What will its final temperature be if (3.35 × 105 J )of thermal energy is transferred to the block?

T = 486.6 K

Explanation:

The final temperature of the block can be found using the following formula:

where,

Q = Thermal Energy Transferred = 3.35 x 10⁵ J

m = mass of aluminum block = 2 kg

C = Specific Heat = 897 J/kg.K

ΔT = Change in Temperature = T - 300 K

T = Final Temperature of the Block = ?

Therefore,

T = 486.6 K

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y