A wire of length 4m, radius lmm is extended by 2.5mm by a load of 200N Calculate the energy stored in the wire and the strain energy per unit volume

Explanation:

Given : L=2 m A=0.0225mm

2

=0.0225×10

−6

m

3

F=100 N

Stress =

A

F

=

0.0225×10

−6

100

=4.4×10

9

N/m

2

Energy stored U=

2

1

×

Y

(stress)

2

×AL

Or U=

2

1

×

20×10

10

(4.4×10

9

)

2

×(0.0225×10

−6

)(2)=2.222 J

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resonant frequency