. A thin layer of a transparent material with an index of refraction of 1.31 is used as a non-reflective coating on a surface of glass with an index of refraction of 1.43. What should the minimum thickness of the material be for it to be

The minimum thickness of the material is 114.5 nm

Explanation:

The remaining part of the question is as follows

What should the minimum thickness of the material be for it to be nonreflecting for light of wavelength 600 nm (in a vacuum)? Please give details of your reasoning.

Both reflections occur against a surface of higher index of refraction, so there is a phase shift at each reflection. The phase shifts cancel each other out, so if we want the emerging rays to be out of phase, we must have

Given

Index of refraction = 1.31

Index of refraction = 1.43

As we know

Here t is the thickness

represents the phase shift

n is the refraction index

Substituting the given values we get

nm

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.